20t=-16t^2-32+5

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Solution for 20t=-16t^2-32+5 equation: 



20t=-16t^2-32+5

We move all terms to the left:

20t-(-16t^2-32+5)=0

We get rid of parentheses

16t^2+20t+32-5=0

We add all the numbers together, and all the variables

16t^2+20t+27=0

a = 16; b = 20; c = +27;
Δ = b2-4ac
Δ = 202-4·16·27
Δ = -1328
Delta is less than zero, so there is no solution for the equation

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